Wednesday, May 20, 2009

Question on Acceleration at which human heart pump the Blood

A simple word problem on finding acceleration of a human heart, pumping the blood in uniform motion and non uniform motion through out the body. Problem is all about acceleration at which heart functioning.

Topic : Human heart accelerating blood with certain velocity.

Rate of change of velocity is called as acceleration, here is one example for how to find acceleration.

Question : The left ventricle of the heart accelerate blood from rest to a velocity of 26cm/s. IF the displacement of the blood during the acceleration is 2cm, determine the acceleration in cm/s2?

Solution :

V initial = 0cm/s
V final = 26cm/s

Displacement = s = 2 cm

a = acceleration
V final2 = V initial2 + 2*a*s

262 = 02 + 2*a*2

a = (262 - 02)/4
= (676-0)/4=169 cm/sec2
=1.69m/sec2

So a = 169 cm/sec2=1.69m/sec2




To know more about acceleration and type of acceleration please write to our physics help.

No comments:

Post a Comment