problem on rays of light

Topic :- Rays of Light

In optics, a ray is an idealized narrow beam of light. Rays are used to model the propagation of light through an optical system, by dividing the real field of light up into discrete rays that can be computationally propagated through the system by the techniques of rays of light.

Here is a problem on rays ,which explain more...


Question:-
A ray of light incident upon a plane mirror makes an angle of 36 degrees with the mirror. What is the angle between the incident ray and the reflected ray?


ANSWER: 108 degrees


Here the of light incident upon a plane mirror makes an angle=36 degrees with the mirror

So normal angle=90 degrees

So angle between the incident ray and the normal ray= 54 degrees

And the angle between the normal ray and the reflected = 54 degrees

So here,

The angle between the incident ray and the reflected ray=54+54=108 degrees

For more help on Rays ,you can reply me .

problem on rays of light

Topic :- Rays of Light

In optics, a ray is an idealized narrow beam of light. Rays are used to model the propagation of light through an optical system, by dividing the real field of light up into discrete rays that can be computationally propagated through the system by the techniques of rays of light.

Here is a problem on rays ,which explain more...


Question:-
A ray of light incident upon a plane mirror makes an angle of 36 degrees with the mirror. What is the angle between the incident ray and the reflected ray?


ANSWER: 108 degrees


Here the of light incident upon a plane mirror makes an angle=36 degrees with the mirror

So normal angle=90 degrees

So angle between the incident ray and the normal ray= 54 degrees

And the angle between the normal ray and the reflected = 54 degrees

So here,

The angle between the incident ray and the reflected ray=54+54=108 degrees

For more help on Rays ,you can reply me .

Question on Acceleration at which human heart pump the Blood

A simple word problem on finding acceleration of a human heart, pumping the blood in uniform motion and non uniform motion through out the body. Problem is all about acceleration at which heart functioning.

Topic : Human heart accelerating blood with certain velocity.

Rate of change of velocity is called as acceleration, here is one example for how to find acceleration.

Question : The left ventricle of the heart accelerate blood from rest to a velocity of 26cm/s. IF the displacement of the blood during the acceleration is 2cm, determine the acceleration in cm/s²?

Solution :

V initial = 0cm/s
V final = 26cm/s

Displacement = s = 2 cm

a = acceleration
V final² = V initial² + 2*a*s

26² = 0² + 2*a*2

a = (26² - 0²)/4
= (676-0)/4=169 cm/sec²
=1.69m/sec²

So a = 169 cm/sec²=1.69m/sec²



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